## WILL AWARD BRAINLIEST!!! there are 4 questions. 1. Sergio’s investment of \$4,000 earns 2% interest compounded annually. What wi

Question

WILL AWARD BRAINLIEST!!! there are 4 questions.

1. Sergio’s investment of \$4,000 earns 2% interest compounded annually. What will be the value of Sergio’s investment in 7 years?

a. \$4,594.74

b. \$4,560.00

c. \$594.74

d. Not here

2. Danny invests \$10,000 in a savings account that pays 3.5% simple interest. If Danny does not make any additional deposits or withdrawals, how much will be in the account after 7 years?

a. \$2,450

b. \$12,450

c. \$11,750

d. Not here

3. Angel deposited \$6,000 in an account that pays 6% interest compounded annually. Which expression can be used to determine the value of his investment after 5 years?

a. 6000(1.06)^5

b. 6000(0.06)^5

c. 6000+6000(0.06)^(5)

d. 6000(1.06)^(5)

4. Felicia invests \$25,000 in a savings account that pays 2.75% simple interest. How much interest does Felicia earn each year?

a. \$787.50

b. \$625.00

c. \$657.50

d. \$687.50

thanks!

in progress 0
2 months 2021-09-21T14:11:23+00:00 1 Answer 0 views 0

1. Step-by-step explanation:

To solve these problems we will use these formulas

Compound interest is formula

A = P(1 +r)^t

A = final amount

P = initial principal balance

r = interest rate

t = number of time periods elapsed

The Simple interest formula is

A = P (1 + rt)

1. Compound interest

Principal p= \$4000

Time t = 7years

Rate r= 2%= 2/100= 0.02

A= 4000(1+0.02)^7

A=4000(1.02)^7

A= 4000*1.1486

A=4594.74

A. \$4594.74

2. Simple interest

P= \$10000

Rate r= 3.5%=3.5/100= 0.035

Time t= 7 years

A= 10000(1+0.035*7)

A= 10000(1+0.245)

A= 10000(1.245)

A= \$12450

B. \$12450

3 compound interest

Given

Principal = \$6000

Rate r= 6%= 6/100= 0.06

Time t =5 years

A= 6000(1+0.06)^5

A= 6000(1.06)^5

A. 6000(1.06)^5

4. Simple interest

Principal p = \$25000

Rate r= 2.75%= 2.75/100= 0.025

Time t= 1 year

A= 25000(1+0.025*1)

A= 25000(1.025)

A=\$25625

She will earn interest of

25000-25625=\$625 yearly