Write an equation of the line that passes through (3, 8) and is perpendicular to the line y = 5x – 4

Question

Write an equation of the line that passes through (3, 8) and is perpendicular to the line y = 5x – 4

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Genesis 1 month 2021-09-12T05:57:14+00:00 1 Answer 0

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    2021-09-12T05:58:49+00:00

    Answer:

    y = -1/5x + 48/5 or y = -1/5x + 8.6

    Step-by-step explanation:

    Using the equation of line

    y – y_1 = m(x – x_1)

    First find the slope

    y = 5x – 4

    Note, if two lines are perpendicular, their slope will be negative reciprocal

    Slope = m = -1/5

    Using the equation

    y -y_1 = m(x – x_1)

    With the point ( 3, 8)

    x_1 = 3

    y_1 = 8

    y – 8 = -1/5 ( x – 3)

    y – 8 = -1(x -3)/5

    Open the bracket

    y – 8 =( -x +3 )/ 5

    y = (-x +3)/5 + 8

    LCM Is 5..

    y =( -x +3 + 40)/5

    y = (-x + 43)/5

    We can still separate

    y = -x/5 + 43/5

    y = -1/5x + 43/5

    y = -1/5x + 8.6

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45:7+7-4:2-5:5*4+35:2 =? ( )