Write the expression, log 3x – 2 logx- log(2+y)], as a single logarithm.

Question

Write the expression, log 3x – 2 logx- log(2+y)], as a single logarithm.

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Adalyn 1 week 2021-10-04T20:31:34+00:00 1 Answer 0

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    2021-10-04T20:32:55+00:00

    Answer: log(  3 /x[2+y])

    Step-by-step explanation:

    Hi to answer this question we have to follow the next steps:

    log 3x – 2 logx- log(2+y)]

    Simplify the second term

    log 3x –  logx²- log(2+y)]

    Use the quotient property of logarithms in the first 2 terms

    log (3x / x²)-  log(2+y)

    log (3 / x)-  log(2+y)

    Use the quotient property of logarithms again

    log (3/x ÷ [2+y])

    Combine

    log ( 3 / x  [2+y])

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