Write the expression, log 3x – 2 logx- log(2+y)], as a single logarithm. Question Write the expression, log 3x – 2 logx- log(2+y)], as a single logarithm. in progress 0 Math Adalyn 1 week 2021-10-04T20:31:34+00:00 2021-10-04T20:31:34+00:00 1 Answer 0

## Answers ( )

Answer:log( 3 /x[2+y])Step-by-step explanation:Hi to answer this question we have to follow the next steps:

log 3x – 2 logx- log(2+y)]

Simplify the second term

log 3x – logx²- log(2+y)]

Use the quotient property of logarithms in the first 2 terms

log (3x / x²)- log(2+y)

log (3 / x)- log(2+y)

Use the quotient property of logarithms again

log (3/x ÷ [2+y])

Combine

log ( 3 / x [2+y])