Write the equation in slope-intercept form of a line that has a slope of One-third and passes through the point (-6, 0). y = one-third
Question
Write the equation in slope-intercept form of a line that has a slope of One-third and passes through the point (-6, 0).
y = one-third x
y = one-third x minus 6
y = one-third x minus 2
y = one-third x + 2
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2022-02-19T05:34:00+00:00
2022-02-19T05:34:00+00:00 2 Answers
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Answer:
y = one-third x + 2
Step-by-step explanation:
Did on edge
Slope-intercept form: y = mx + b
(m is the slope, b is the y-intercept or the y value when x = 0 –> (0, y) or the point where the line crosses through the y-axis)
You know:
m = [tex]\frac{1}{3}[/tex] So substitute/plug it into the equation
y = mx + b
[tex]y=\frac{1}{3} x+b[/tex] To find b, plug in the point (-6, 0) into the equation, the isolate/get the variable “b” by itself
[tex]0=\frac{1}{3} (-6)+b[/tex]
0 = -2 + b Add 2 on both sides to get “b” by itself
0 + 2 = -2 + 2 + b
2 = b
[tex]y=\frac{1}{3} x+2[/tex] Your answer is the 4th option