Write the equation in slope-intercept form of a line that has a slope of One-third and passes through the point (-6, 0). y = one-third

Question

Write the equation in slope-intercept form of a line that has a slope of One-third and passes through the point (-6, 0).
y = one-third x
y = one-third x minus 6
y = one-third x minus 2
y = one-third x + 2

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Katherine 3 months 2022-02-19T05:34:00+00:00 2 Answers 0 views 0

Answers ( )

    0
    2022-02-19T05:35:03+00:00

    Answer:

    y = one-third x + 2

    Step-by-step explanation:

    Did on edge

    0
    2022-02-19T05:35:09+00:00

    Slope-intercept form:  y = mx + b

    (m is the slope, b is the y-intercept or the y value when x = 0 –> (0, y) or the point where the line crosses through the y-axis)

    You know:

    m = [tex]\frac{1}{3}[/tex]      So substitute/plug it into the equation

    y = mx + b

    [tex]y=\frac{1}{3} x+b[/tex]   To find b, plug in the point (-6, 0) into the equation, the isolate/get the variable “b” by itself

    [tex]0=\frac{1}{3} (-6)+b[/tex]

    0 = -2 + b         Add 2 on both sides to get “b” by itself

    0 + 2 = -2 + 2 + b

    2 = b

    [tex]y=\frac{1}{3} x+2[/tex]       Your answer is the 4th option

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45:7+7-4:2-5:5*4+35:2 =? ( )