Write the equation of the line that passes through (-1, 11) and (3, -5)

Question

Write the equation of the line that passes through (-1, 11) and (3, -5)

in progress 0
Caroline 2 weeks 2021-09-28T11:22:43+00:00 1 Answer 0

Answers ( )

    0
    2021-09-28T11:24:11+00:00

    Answer:

    y= -4x+7

    Step-by-step explanation:

    The equation of a line is usually written in the form of y=mx+c, where m is the gradient and c is the y-intercept.

    Let’s find the gradient of the line first.

    gradient =  \frac{y1 - y2}{x1 - x2}

    Using the above formula,

    m =  \frac{11 - ( - 5)}{ - 1 - 3}  \\ m =  \frac{11 + 5}{ - 4}  \\ m =  \frac{16}{ - 4}  \\ m =  - 4

    Susbt. m= -4 into the equation:

    y= -4x +c

    Subst. a coordinate to find c.

    When x=3, y= -5,

    -5= -4(3) +c

    -5= -12 +c

    c= 12 -5

    c=7

    Thus the equation of the line is y= -4x +7.

Leave an answer

45:7+7-4:2-5:5*4+35:2 =? ( )