Write the general equation for the circle that passes through the points (- 5, 0), (0, 4), and (2, 4). You must include the appropriat

Question

Write the general equation for the circle that passes through the points (- 5, 0), (0, 4), and (2, 4).
You must include the appropriate sign (+ or -) in your answer. Do not use spaces in your answer.
4x² + 4y² ___x ___y ___ = 0

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Mia 2 weeks 2021-11-19T19:51:55+00:00 1 Answer 0 views 0

Answers ( )

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    2021-11-19T19:53:42+00:00

    Answer:

    [tex]4x^2+4y^2+72x-81y+260=0

    Step-by-step explanation:

    For the point (-5,0) we have

    4*(-5)^2+4*0^2+a*(-5)+b*0+c=0

    100-5a+c=0

    -5a+c=-100…….(1)

    Fro the point (0,4) we have:

    4*0^2+4*4^2+a*0+b*4+c=0

    64+4b+c=0

    4b+c=-64…..(2)

    For the point (2,4) we have:

    4*4+4*16+2a+4b+c=0

    16+64+2a+4b+c=0

    2a+4b+c=80…..(3)

    (3)-(2):

    2a+4b+c-4b-c=80+64

    2a=144

    a=72

    So we have:

    -5*72+c=-100

    c=260

    And from (2) we have

    4b+260=-64

    b=-81

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45:7+7-4:2-5:5*4+35:2 =? ( )