You have a bag with 100 pennies. One of the 100 pennies is weighted so that it lands on heads 90% of the time. The rest of them land on head

Question

You have a bag with 100 pennies. One of the 100 pennies is weighted so that it lands on heads 90% of the time. The rest of them land on heads 50% of the time. You pull out a random coin and ip it ve times in a row. It lands on heads every single time. What is the probability that it is the weighted penny?

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Faith 2 weeks 2021-10-01T06:25:52+00:00 1 Answer 0

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    2021-10-01T06:27:35+00:00

    Answer:

    0.160275

    Step-by-step explanation:

    P(5 time heads) =P(fair penny and 5 time heads + weighted penny and  5 time heads)

    probability of fair penny = 99/100 (as one is removed)

    probability of heads = 50% = 0.5 flipped 5 times

    probability of weighted penny = 1/100

    probability of heads for this penny = 90% = 0.9

    substituting, we have

    =(99/100) * (1/2)*5  +  (1/100) * (0.9)5  = 0.036842

    hence from Bayes theorem

    P(weighted penny | 5 time heads) =P(weighted penny and 5 time heads) / P(5 time heads)

    =(1/100)*(0.9)5 /0.036842 =0.160275

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45:7+7-4:2-5:5*4+35:2 =? ( )